www.bing.com/ck/a?!&&p=b892327665ba52a191563ab17c95e83a35b064c9dcf16215a1a92597743ff3a8JmltdHM9MTc3MjU4MjQwMA&ptn=3&ver=2&hsh=4&fclid=2b50db80-90fb-64ee-3018-cc9391c5656e&u=a1aHR0cHM6Ly93d3cuZGF0YWxvdW5nZS5jb20vdGhyZWFkLzMxODk1MDk3LW5laWwtcGF0cmljay1oYXJyaXMtYmVpbmctY2FsbGVkLW91dC1vbi1zb2NpYWwtbWVkaWEtZm9yLW9sZC1jb21tZW50cy1tYWRlLWFib3V0LW5pY2stam9uYXM&ntb=1
Oct 26, 2022 · NPH admitted several years ago (on tv) that he used to crush on Nick Jonas before Nick was of legal age.
www.reddit.com/r/hospitalist/comments/1ovsrc0/am_i_billing_too_many_99223/
My first audit showed my billing as 33% 99223 and 66% 99222 - this was my first 3 months as attending. I was told then by billers that I was "billing too many 3s" with my admits. I asked them what is ...
www.reddit.com/r/teenagers/comments/1q3z3ur/my_stepmom_got_us_some_shrimp_and_my_dad_insisted/
Despite him refusing to admit he’s neurodivergent he got so excited about pulling out his Geiger counter and testing the shrimp with it...
www.reddit.com/r/Showerthoughts/comments/2uvvsv/masturbating_in_the_bathroom_at_work_is_the/
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arxiv.org/abs/2105.01895v1
In 1991, Shalaby conjectured that any $\mathbb{Z}_{n}$, where $n\equiv 1$ or $3\pmod{8},\ n\ge 11$, admits a strong Skolem starter. In 2018, the authors explicitly constructed some infinite "cardioidal" families of strong Skolem starters. No other in...
arxiv.org/abs/2001.02220v1
In 1991, N. Shalaby conjectured that any additive group $\mathbb{Z}_n$, where $n\equiv1$ or 3 (mod 8) and $n \geq11$, admits a strong Skolem starter and constructed these starters of all admissible orders $11\leq n\leq57$. Shalaby and et al. [O. Ogan...
arxiv.org/abs/1901.07514v2
In 1991, Shalaby conjectured that any additive group $\mathbb{Z}_n$, where $n\equiv1$ or 3 (mod 8) and $n \geq11$, admits a strong Skolem starter and constructed these starters of all admissible orders $11\leq n\leq57$. Only finitely many strong Skol...
arxiv.org/abs/1612.09173v1
The symmetric group $\mathfrak S_{n+1}$ of degree $n+1$ admits an $n$-dimensional irreducible $\mathbf Q \mathfrak S_n$-module $V$ corresponding to the hook partition $(2,1^{n-1})$. By the work of Craig and Plesken we know that there are $σ(n+1)$ ma...
arxiv.org/abs/2208.10666v3
We calculate the homology groups of certain 2-connected 7-manifolds admitting quasi-regular Sasaki-Einstein metrics. These manifolds are links that arise as Thom-Sebastiani sums of chain type singularities and cycle type singularities. Among these li...
www.reddit.com/r/GirlsNextDoorBUNNIES/comments/1ixeauc/sara_underwood_plastic_surgery/
Sara recently posted about replacing her implants with Dr. Barrett and it actually looks so natural. She is aging gracefully and just seems so genuine. She's so real for actually admitting to it and p...
www.reddit.com/r/cats/comments/1qan4av/odd_question_but_how_do_i_get_my_cat_to_stop/
I’ll admit that it was very cute and entertaining at first, but at this point, oh my god. She jump scares me multiple times a day by slamming on keys, and wakes me up periodically with her bad music...
www.bing.com/ck/a?!&&p=2f70a1d17c849daeb168b051e8b6e2d157b5a6b8ddc8f074391d3e980b91a6bcJmltdHM9MTc3MjU4MjQwMA&ptn=3&ver=2&hsh=4&fclid=390f634f-b853-635f-27d2-745cb927623d&u=a1aHR0cHM6Ly9vcGVuYWkuY29tL2luZGV4L2NoYXRncHQv&ntb=1
Nov 30, 2022 · We’ve trained a model called ChatGPT which interacts in a conversational way. The dialogue format makes it possible for ChatGPT to answer followup questions, admit its mistakes, …
www.reddit.com/r/librarians/comments/g95hih/should_i_go_to_simmons/
Hi all, I had originally received the advice to seek out an advanced degree in my field, English because of my GPA and enjoyment of research. Unfortunately, the only school I ended up receiving admit...
arxiv.org/abs/2506.14778v3
We establish that any affine manifold $(M,\nabla)$ endowed with a parallel volume form $ω,$ admits, in any conformal class of Riemannian metrics, a representative $H$ for which $\nabla$ is the Levi-Civita connection. This provides a constructive pro...
arxiv.org/abs/math/0511303v4
Geodesically complete affine manifolds are quotients of the Euclidean space through a properly discontinuous action of a subgroup of affine Euclidean transformations. An equivalent definition is that the tangent bundle of such a manifold admits a f...
arxiv.org/abs/1110.5369v2
The cohomology of the configuration space of n points in R^3 admits a symmetric group action and has been shown to be isomorphic to the regular representation. One way to prove this is by defining an S^1-action whose fixed point set is the complement...
arxiv.org/abs/2112.07951v1
This paper develops the study of Fox pairings of a group $G$ from the viewpoint of group cohomology. We compute some cohomology groups of Fox pairings of $G$, where $G$ admits a Poincaré duality group pair. We also suggest fundamental Fox pairings a...
www.bing.com/ck/a?!&&p=cbc90f0f956b6520449df33cf46a1dc03340d8233a16f8a68b1e0979aed5e5cdJmltdHM9MTc3MjU4MjQwMA&ptn=3&ver=2&hsh=4&fclid=002e4762-d8b6-6dd9-05e0-5071d9b06c69&u=a1aHR0cHM6Ly93d3cuYnV0dGUuZWR1L2FkbWlzc2lvbnMv&ntb=1
Admissions & Records. Transcript requests available. Admissions Requirements Butte College admits all high school graduates or the equivalent, and any persons 18 years of age or over who are …
www.bing.com/ck/a?!&&p=81dfe092766e80195a26647e18d180509f90fe4d6779ff3eb86436f6ff473d8cJmltdHM9MTc3MjU4MjQwMA&ptn=3&ver=2&hsh=4&fclid=026050e6-43d8-6503-2659-47f54232648d&u=a1aHR0cHM6Ly9vcGVuYWkuY29tL2luZGV4L2NoYXRncHQv&ntb=1
Nov 30, 2022 · We’ve trained a model called ChatGPT which interacts in a conversational way. The dialogue format makes it possible for ChatGPT to answer followup questions, admit its mistakes, …
www.reddit.com/r/politics/comments/ipk2w9/megathread_trump_says_he_deliberately_played_down/
President Donald Trump admitted that he wanted to publicly downplay the threat of the coronavirus even as his advisors warned him about the dangers of the disease, Bob Woodward wrote in his forthcomin...
